Enthelpy change for an ideal gas

In summary, the equation says that the internal energy is equal to the change in temperature plus the change in pressure. If the temperature and pressure are constant, then the internal energy is equal to the initial temperature. If the temperature or pressure is not constant, then the internal energy is equal to the final temperature.
  • #1
babita
61
0

Homework Statement



I'm not able to understand the following equation
ΔH = ΔU + (Δn)RT
firstly if T is taken to be constant (as the book says), ΔU = 0
if T is not constant then which T i am supposed to put in? initial or final?

Homework Equations


please help. Thank you.


The Attempt at a Solution

 
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  • #2
babita said:

Homework Statement



I'm not able to understand the following equation
ΔH = ΔU + (Δn)RT
firstly if T is taken to be constant (as the book says), ΔU = 0
if T is not constant then which T i am supposed to put in? initial or final?

Homework Equations


please help. Thank you.

The Attempt at a Solution


Hi babita! :smile:

Looks to me that your equation is not right.
I think it should be:
ΔH = ΔU + Δ(nRT)

Assuming n is constant, this is the same as:
ΔH = ΔU + nRΔT

Does that answer your question?
To give a more extensive explanation:

H is defined as H=U+PV.
With the ideal gas law PV=nRT, it follows that H=U+nRT.
For a change in H we get:
ΔH=Δ(U+nRT)=ΔU+Δ(nRT)
 
  • #3
hi:smile:
yeah that would have made sense but its written "at constant temperature" every where :'(
 
  • #4
Okay, so apparently the amount of matter does not stay constant and you have a Δn.

If the temperature is constant then the initial temperature is the same as the final temperature.

Your equation becomes:
ΔH=ΔU+Δ(nRT)=ΔU+(Δn)RT.

And as you surmised, with T constant, you have ΔU=0, so you get:
ΔH=(Δn)RT
 
  • #5
I like Serena said:
Okay, so apparently the amount of matter does not stay constant and you have a Δn.
amount of matter may or may not change...Δn means no of moles of gaseous products minus no of moles of gaseous reactants

THAT is my confusion...at constant T , ΔU makes no sense
 
  • #6
Actually, in retrospect ΔU does make sense if the number of moles changes.
My bad.

For an ideal gas you have: U=n Cv T
With constant T, the change in U is:
ΔU=(Δn) Cv T
 
  • #7
Cv is heat capacity at constant volume...i don't think volume is constant here...in my book the equation have been derived assuming constant T & P.
 
  • #8
Also Internal energy of an ideal gas is directly proportional to T
 
  • #9
Cv is indeed the heat capacity at constant volume.

However, it turns out that the formula U=n Cv T holds for an ideal gas, even if the volume is not constant.

That's not really relevant here though.
As you said internal energy U is directly proportional to T.
U is also directly proportional to the number of moles n.
 
  • #10
I like Serena said:
Cv is indeed the heat capacity at constant volume.

However, it turns out that the formula U=n Cv T holds for an ideal gas, even if the volume is not constant.

.

yeah sry ...that was silly
 
  • #11
and yes U is proportional to n, equation makes sense at constant T ...missed that point... thanks :)
 
  • #12
You're welcome. :)
 

1. What is enthalpy change for an ideal gas?

Enthalpy change for an ideal gas refers to the change in the total energy of a gas system at a constant pressure. It takes into account the internal energy of the gas, as well as any work done on or by the gas.

2. How is enthalpy change for an ideal gas calculated?

The enthalpy change for an ideal gas can be calculated using the formula ΔH = ΔU + PΔV, where ΔH is the enthalpy change, ΔU is the change in internal energy, P is the pressure, and ΔV is the change in volume.

3. What is the significance of enthalpy change for an ideal gas?

Enthalpy change for an ideal gas is significant because it allows us to measure the amount of heat energy absorbed or released by a gas system during a process. This is important in understanding and predicting the behavior of gases in various situations.

4. How does the enthalpy change for an ideal gas differ from other types of enthalpy change?

The enthalpy change for an ideal gas differs from other types of enthalpy change in that it only takes into account the changes in internal energy and volume of the gas, while other types may also consider changes in other factors such as pressure, temperature, and chemical composition.

5. Can enthalpy change for an ideal gas be negative?

Yes, enthalpy change for an ideal gas can be negative. This indicates that the gas system has released heat energy to its surroundings. A negative enthalpy change can occur during exothermic processes such as combustion or condensation.

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