Find the Plane: Perpendicular to yz-Plane & y=-2, z=4

In summary, the student is trying to determine the equation of a perpendicular plane that has y-intercept at 4 and z-intercept at -2. The normal to the plane is perpendicular to this vector, so the plane is located at (0,1,1). The student is trying to find the equation of the plane using the y- and z-intercepts at 4 and -2, but is having trouble because the normal is not <0, 1, 1>.
  • #1
adrimare
33
0

Homework Statement



Determine the Cartesian equation of the plane that is perpendicular to the yz-plane and has y-intercept 4 and z-intercept -2.

Homework Equations



?

The Attempt at a Solution



I'm pretty sure that the normal to the plane I want to find would be (0,1,1). A y-intercept would go through (0,y,0) and a z-intercept would go through or be (0,0,z). How do I make an equation with a y and z- intercept at 4 and -2 respectively?
 
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  • #2


adrimare said:

Homework Statement



Determine the Cartesian equation of the plane that is perpendicular to the yz-plane and has y-intercept 4 and z-intercept -2.

Homework Equations



?

The Attempt at a Solution



I'm pretty sure that the normal to the plane I want to find would be (0,1,1). A y-intercept would go through (0,y,0) and a z-intercept would go through or be (0,0,z). How do I make an equation with a y and z- intercept at 4 and -2 respectively?
No, the normal to the plane is NOT <0, 1, 1>. The normal is perpendicular to this vector. The plane is perpendicular to the y-z plane. The y-intercept is 4, which means that the point (0, 4, 0) is on the plane. The z-intercept is -2, which means that what point is on the plane?

If you're not already doing so, draw a sketch using a three-dimensional coordinate system. It will help you get your head around these kinds of problems.
 
  • #3


My teacher said to forget about learning how to sketch, so that's out. Is the normal to the plane (1,0,0) then? So (0,4,0) and (0,0,-2) are both on the plane. How would I stick those points on a plane with a Cartesian equation of x=0, then? I need to get a D-value, which I can get from points, I know, but when the equation is 1x + 0y + 0z + D, would the intercepts kind of not really matter? The D-value would be 0, so the equation would be x=0, right? Or am I wrong about the normal again? Or am I supposed to be looking for the direction vector formed by the two intercepts and use that as my normal?
 

1. How do you find the coordinates of a plane perpendicular to the yz-plane?

To find the coordinates of a plane perpendicular to the yz-plane, you need to set the x-value to a constant value, let's say x=k. This means that the plane will pass through all points with the x-coordinate equal to k. The equation of the plane will then be x=k.

2. What is the equation of a plane perpendicular to the yz-plane if y=-2 and z=4?

The equation of a plane perpendicular to the yz-plane can be written as x=k, where k is a constant value. Since the plane is perpendicular to the yz-plane, the x-value does not depend on the y and z values. Therefore, the equation would be x=k, where k is any real number. This means that the plane is a vertical plane passing through all points with the x-coordinate equal to k.

3. How do you graph a plane perpendicular to the yz-plane with the equation x=3?

To graph a plane perpendicular to the yz-plane with the equation x=3, you need to draw a vertical line at x=3. This line will represent all points on the plane with the x-coordinate equal to 3. Since the plane is perpendicular to the yz-plane, it will also extend infinitely in the y and z directions.

4. How many planes can be perpendicular to the yz-plane?

There are infinitely many planes that can be perpendicular to the yz-plane. This is because for any value of x, there is a unique plane that can be perpendicular to the yz-plane. Therefore, there is no limit to the number of planes that can be perpendicular to the yz-plane.

5. What is the relationship between a plane perpendicular to the yz-plane and the x-axis?

A plane perpendicular to the yz-plane is parallel to the x-axis. This is because the x-axis is defined as the line with a constant x-value of 0, and any plane perpendicular to the yz-plane has a constant x-value. Therefore, the plane and the x-axis never intersect and are always parallel to each other.

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