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#8
A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the separation between the plates is d= 0.0242m, what's the potential energy?
v=w/q
not sure, where to begin but...
V= w/q
w=1/2cv sq
F= keqq/r
F= 8.99e9 (6.62e-6)/.0242 sq
Homework Statement
A point charge mass of 0.0788kg and q charge= +6.62 uc is supended by a thread between the vertical plates of a parallege capacitor. If the angle of delflectionis 23.7 degress and the separation between the plates is d= 0.0242m, what's the potential energy?
Homework Equations
v=w/q
The Attempt at a Solution
not sure, where to begin but...
V= w/q
w=1/2cv sq
F= keqq/r
F= 8.99e9 (6.62e-6)/.0242 sq