Calculating # of Electrons in a Ping-Pong Ball w/ Charge of 3.2x10-5C

[AaronLosAl]

Homework Statement

If a ping-pong ball has a charge of 3.2x10-5C, how many too many or to few electrons does it have

Homework Equations

# of electrons=charge/fundamental charge

The Attempt at a Solution

3.2X10-5C/1.6X10-19=
2.0X1014
What do i do now, and i do not get what it means by too many or too few.

 

[AaronLosAl]

Nevermind i did it

 

[m2003]

Based on the given information, we can calculate the number of excess or deficit electrons in the ping-pong ball by using the formula for the number of electrons, which is charge divided by the fundamental charge. In this case, the charge is 3.2x10-5C and the fundamental charge is 1.6x10-19C. Plugging these values into the formula, we get 2.0x1014 electrons.

This means that the ping-pong ball has 2.0x1014 excess electrons compared to a neutral ping-pong ball (which would have an equal number of protons and electrons). This excess charge could have been caused by rubbing the ball against a material, which can transfer electrons and create a charge imbalance.

In terms of too many or too few electrons, it depends on the context and what is considered a "normal" or neutral charge for a ping-pong ball. If we assume that a neutral ping-pong ball has an equal number of protons and electrons (no net charge), then this ball has too many electrons. However, if we consider a ping-pong ball with a charge of 3.2x10-5C to be normal, then this ball has too few electrons (since it has a deficit of 2.0x1014 electrons compared to that). It all depends on the reference point and what is considered a standard or neutral state for a ping-pong ball.