Bogoliubov transformation 3-mode

In summary, the conversation is about a problem with a bogoliubov transformation in spin-wave theory. The person is looking for a transformation for three bosons, but has only found it for one and two-mode bosons. They mention a long Hamiltonian with non-diagonal terms and ask for a known bogoliubov transformation for three different bosons. Another person mentions that a solution exists for fermions and suggests using a vector and unitary transformation to solve the problem. The conversation ends with the person expressing hope for finding a solution.
  • #1
Naibaf
3
0
Hi everyone,

I'm working on spin-wave theory and I have a problem with a bogoliubov transformation.
I must do the transformation with 3 bosons and i have no idea how to do it.
I've only found the transformation for 1 and 2-mode bosons, but not for three...

It exist?

Thanks...



And sorry for my english...
 
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  • #2
Maybe you could provide us with your hamiltonian?
 
  • #3
The hamiltonian is very long, but the idea is that I have, products of bosons operator, for example: a*a + a*b + a*c + b*b + bb + b*c and so on...

Where a, b an c are boson operators.
As there are "non-diagonal" terms, the idea is use Bogoliubov Transformation for make the hamiltonian a diagonal hamiltonian... But for 2 differents bosons, the tranformation is:

alpha_{k} = cosh(theta_{k}) a_{k} - sinh(theta_{k}) b*_{k}, where b* is b-dagger

ans this transformation is like "universal" because everyone use it.
So my question is if there is a known bogoliubov transformation for 3 differents bosons in a hamiltonian...
( I hope you understand my english :) )
 
  • #4
I can certainly tell you that a solution exists, at least in the fermionic case, because the Bogoliubov transformation is used routinely in nuclear physics, where you can have ~100 protons and neutrons. Sorry not to be able to supply the actual solution you want :-)
 
  • #5
In this case, the 3 bosons operators are different, I have: a, b and c.
I guess that for ~100 differents protons the transformation must be huge!

I also guess that the bogoliubov transformation for fermions should not be so different from that of bosons......at least I have some hope! :)
thanks
 
  • #6
So, introducing the vector [tex] A=(a_k, a^*_{-k}, b_k, b^*_{-k},c_k, c^*_{-k})^T[/tex],
you should be able to write your hamiltonian as [tex]H=A^\dagger M(k) A[/tex]. Then you have to find the unitary transformation U which diagonalizes the matrix M, i.e., you have to solve the eigenvalue problem for M. Then the vector of the alphas is UA.
Not a big deal, in principle.
 

1. What is a Bogoliubov transformation 3-mode?

A Bogoliubov transformation 3-mode is a mathematical tool used in quantum mechanics to transform the operators of a system from one set of modes to another set of modes, often with the goal of simplifying the mathematical description of the system.

2. Why is the Bogoliubov transformation 3-mode useful?

The Bogoliubov transformation 3-mode is useful because it allows for the diagonalization of the Hamiltonian of a system, making it easier to analyze and solve. It is also used in many physical systems, such as Bose-Einstein condensates and superconductors.

3. How does a Bogoliubov transformation 3-mode work?

A Bogoliubov transformation 3-mode is a linear transformation that involves changing the operators of a system from one set of modes to another set of modes. This is accomplished by expressing the operators in terms of creation and annihilation operators, and then performing a unitary transformation on these operators.

4. Can a Bogoliubov transformation 3-mode be applied to any system?

No, a Bogoliubov transformation 3-mode is only applicable to systems that can be described by a quadratic Hamiltonian, meaning the terms in the Hamiltonian only involve quadratic operators. Examples of systems that can be described by a Bogoliubov transformation 3-mode include bosonic and fermionic systems.

5. Are there any limitations to using a Bogoliubov transformation 3-mode?

One limitation of using a Bogoliubov transformation 3-mode is that it only applies to systems with a small number of modes. Additionally, it may not accurately describe systems with strong interactions or highly non-linear behavior. In these cases, more advanced mathematical techniques may be required.

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