- #1
NotaPhysicsMan
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Ahhh Double Star Question...AGAIN!
I think my prof really doesn't like us or maybe he simply has an over expectation of our abilities...
As the drawing shows (attached), a pond has the shape of an inverted cone with the top sliced off and has a depth of 5.00m. The atmospheric pressure is 1.01 x 10^5 PA. The circular top surface (radius=R2) and circular bottom surface (radius=R1) of the pond are both parallel to the ground. The magnitude of the force acting on the top surface is the same as the manitude of the force acting on the bottom surface. Obtain a)R2 and b)R1.
Okay, this looks like the question involving two equations of two unknowns. First I know that F1=F2... So P1A=P2A. The other I believe might have to do with the volume of this pond. A normal cone would have a volume of 1/3pie x r^2 x h. But since this is a cut-off cone, I'm lost here. Also, that 60 degrees is quite confusing. I think it may have to do with the area of the middle section when unfolded, a trapezoid shape perhaps? Any Ideas appreciated!
Thanks.
I think my prof really doesn't like us or maybe he simply has an over expectation of our abilities...
As the drawing shows (attached), a pond has the shape of an inverted cone with the top sliced off and has a depth of 5.00m. The atmospheric pressure is 1.01 x 10^5 PA. The circular top surface (radius=R2) and circular bottom surface (radius=R1) of the pond are both parallel to the ground. The magnitude of the force acting on the top surface is the same as the manitude of the force acting on the bottom surface. Obtain a)R2 and b)R1.
Okay, this looks like the question involving two equations of two unknowns. First I know that F1=F2... So P1A=P2A. The other I believe might have to do with the volume of this pond. A normal cone would have a volume of 1/3pie x r^2 x h. But since this is a cut-off cone, I'm lost here. Also, that 60 degrees is quite confusing. I think it may have to do with the area of the middle section when unfolded, a trapezoid shape perhaps? Any Ideas appreciated!
Thanks.