Determinants of matrices greater than 3x3

smize

I am wondering how one would find a the determinant of a 4x4 or greater. This isn't an urgent question, just a curiosity.

voko

http://en.wikipedia.org/wiki/Laplace_expansion

AlephZero

That is "correct", and an interesting theoretical result, but it's a hopelessly inefficient way to calculate the determinant of a general matrix, because it takes of the order of n! operations for an n x n matrix.

A much more efficient way is to do row operations on the matrix which don't change the value of the determinant (or only multiply it by -1), but systematically change the matrix so that all the entries below the diagonal are zero. The determinant is then just the product of the diagonal terms. In the worst case, that takes about n³ operations. For a 10 x 10 matrix, n³ = 1,000 and n! = about 3.6 million, so one way is about 3600 times faster than the other!

smize

By chance, could you give an example of how to do row operations to find the determinant?

voko

Whenever I get to compute a det with n >= 3 MANUALLY, I use this method. Possibly because I remember it by heart. Doing arbitrary n dets most efficiently is a distinctly different matter.

smize

At the moment, it is the ONLY method I have learned. (I am self-teaching myself Multidimensional Mathematics until classes start in 3 weeks).

Bohrok

Here's a good explanation of this method:
http://tutorial.math.lamar.edu/Class...Reduction.aspx