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A question about particle mass |
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| Nov30-12, 10:03 PM | #18 |
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A question about particle mass |
| Dec1-12, 01:11 PM | #19 |
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The problem with rearranging it that way is that its slightly miss-using the equation. The m in E=mc2 is "rest mass", not relativistic mass.
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| Dec1-12, 01:13 PM | #20 |
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Leonard Susskind talked about this in one of his Relativity Lectures
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| Dec1-12, 01:27 PM | #21 |
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| Dec1-12, 01:44 PM | #22 |
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The number is [itex]\approx7.37\times10^{-51}kg[/itex]. I doubt that there is an elementary particle with that mass for a number of reasons.
First, there is no reason to expect that there would be. That doesn't mean that there isn't, but the chance of there being one is about the same as any other number. Second, and more importantly, this is about 20 orders of magnitude less than the any other known elementary particles. Perhaps there are smaller particles that we don't know about, but that would be 100% speculation. P.S. Don't take people's comments personally. The internet can make things sound mean when there was no intention of that. If you are interested in physics you should A) learn to be told you're wrong (this will happen more often than anything else) B) try to figure it out on your own. If you plug the numbers in and check on Wikipedia (more less all that I did) you'll see that numbers don't work out to be anything meaningful. If they did... you could ask why and you would get the answer "by chance" |
| Dec4-12, 05:56 PM | #23 |
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| Dec6-12, 05:08 PM | #24 |
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I still got the same mass after I did c times plancks length squared over gravitational constant (from GM/d^2)
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| Dec6-12, 05:22 PM | #25 |
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No you didn't. Plank's length is meters. Squared is m². c is m/s, so you have m³/s. Gravitational constant is N(m/kg)². So your final result is m³kg²/(m²N*s) = m*kg²/(N*s) = m*kg²/(kg*m/s) = kg*s. Your answer isn't even in kilograms, so whatever you got, it isn't mass.
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