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josh28
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Homework Statement
A 1600kg jet engine is fastened to the fuselage of a passenger jet by just three bolts (this is the usual practice). Assume that each bolt supports one-third of the load.
(b) During flight, the plane encounters turbulence, which suddenly imparts an upward vertical acceleration of 2.8 m/s2 to the plane. Calculate the force on each bolt now.
Homework Equations
F = ma
The Attempt at a Solution
The force acting on the engine is the sum of all forces acting on the engine because of Newton's second law. So first I found the force of gravity on the engine
F=ma
F=1600(9.8)
F=15,680 N
then I found the force the turbulence had on the engine
F=1600(-2.8)
F= -4480 N
Then the sum of these forces is -4480 + 15,680 = 11,200
Then I divided this by 3, for the force on each bolt and got 3,733 N.
But when I typed this answer in it was not correct and I do not know what I am doing wrong.