Calculating Volume of Wedge Cut from Maple Tree | Integration Problem

In summary, the conversation discusses the method for finding the volume of a wedge of wood cut from a maple tree by a lumberjack. The process involves slicing the wedge into triangles and integrating the area of each slice to find the total volume. The given diameter of the tree is 0.9m, resulting in a volume of 0.06075 m^3.
  • #1
planauts
86
0
Hi, I am having a lot of trouble with this problem.

Homework Statement



A lumberjack is preparing to cut down a large maple tree. With a chain saw, he makes a horizontal cut exactly halfway through the trunk, and then makes a second cut at 45 degrees, meeting the first cut along the diameter. Determine the volume of the wedge of wood cut out if the diameter is 0.9m.

Homework Equations


Hint: Take the element of integration to be a vertical slice parallel to the thin edge of the wedge.
ANSWER: 0.06075 m^3

The Attempt at a Solution


[PLAIN]http://img232.imageshack.us/img232/8066/80795462.gif

dV = (area)*(dy)
I think the area would be: r(theta) = r(pi/4) = (0.9)(pi/4)
But I am stuck after that...I don't even think I am on the right track...

Thanks for your help!
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
Well, the idea is that to find the volume of the wedge, you should slice it up, express the area of each wedge in terms of variables, and then integrate that expression to give the volume of the whole wedge.
So, how are you going to slice up the wedge?
What you have written down so far doesn't make much sense. It seems as though you're trying to slice the wedge so that you get triangles. That makes sense. But not all the triangles you get are going to have the same area. How do you express the area of each slice in terms of what variables you're given?
It looks like you tried to find the area of one triangle by using r*theta, but that's not even the formula for the area of a triangle, which is 1/2(base)(ht).
 
  • #3
A better way to picture this is to first imagine half of a circle on the xy plane. Then place triangles on the circle perpendicular to the plane with the right angle of the triangle sitting on the curve of the circle. Now the length is bounded by this semicircle so the length changes from 0->0.45->0 as you move the triangle from the edge of the circle to the middle to the other edge. Hope this helps.
 

What is "Volumes by Integration"?

Volumes by integration is a mathematical technique used to calculate the volume of a solid object by breaking it down into infinitesimally small slices, finding the area of each slice, and then adding up all the areas to get the total volume. It is commonly used in calculus and is based on the concept of integration.

What is the formula for calculating volumes by integration?

The formula for calculating volumes by integration is V = ∫a^b A(x) dx, where V is the volume, a and b are the bounds of the solid object, and A(x) is the area of the cross-section at a certain point x.

What are some common applications of volumes by integration?

Volumes by integration is used in a wide range of fields, including physics, engineering, and architecture. It is commonly used to calculate the volume of irregularly shaped objects, such as a pyramid or a curved structure.

What are the steps involved in calculating volumes by integration?

The steps involved in calculating volumes by integration are as follows: 1) Identify the solid object and determine the bounds of integration, 2) Express the cross-sectional area in terms of a variable, such as x or y, 3) Use the integration formula to find the volume, 4) Solve the integral and evaluate it between the bounds of integration, and 5) Interpret the result as the volume of the solid object.

What are some common challenges in using volumes by integration?

One common challenge in using volumes by integration is determining the bounds of integration, especially for irregularly shaped objects. Another challenge is setting up the integral and finding the correct expression for the cross-sectional area. Additionally, numerical errors can occur if the integration is not done accurately, leading to incorrect results.

Similar threads

  • Calculus and Beyond Homework Help
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
4
Views
2K
  • Calculus and Beyond Homework Help
Replies
9
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
1K
  • Calculus and Beyond Homework Help
Replies
14
Views
3K
  • Calculus and Beyond Homework Help
Replies
10
Views
2K
  • Calculus and Beyond Homework Help
Replies
8
Views
8K
  • Calculus and Beyond Homework Help
Replies
1
Views
909
  • Calculus and Beyond Homework Help
Replies
12
Views
4K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
Back
Top