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Homework Statement
Hi! I am new to Real Analysis. Please let me know if my solution is alright. Thanks.
epsilon=e
Show that |x-a|< e IFF a-e < x < a+e
The Attempt at a Solution
Assume |x-a|< e. Prove, a-e < x < a+e
|x-a|< e
-e < x-a < e
a-e < x < a+e
Assume a-e < x < a+e. Prove |x-a|< e.
a-e < x < a+e
-e < x-a < e
|x-a|< e