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kkmonte
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Homework Statement
A support column is compressed 2.46 x 10^ -4m under a weight of 5.42 X 10^5N. how much is the column compressed under a weight of 4.8 X10^6N?
Homework Equations
F=KX
The Attempt at a Solution
By using that equation, I get 542000 = .000246K
Solve for K, and I get a huge number, 2,203,252,032.52
Then by using that number as my new K, and solving for the compressed distance with the new weight, I get 0.0022 m.
Is that the right answer?
Similarly, I figured I could just make a ratio proportion of:
.000246....X
------------- = ----------------
542,000....4,800,000
Which also gives me an answer of 0.0022 m (2.2 X 10^ -3). Is this correct?
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