- #1
markelmarcel
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Homework Statement
A student has 4.00g of Copper Chloride (CuCl2) and 25.0 g of Aluminum (Al). Calculate the mass of each reactant and product present at the end of the reaction. Show your calculations.
Homework Equations
3 CuCl2 + 2Al [tex]\rightarrow[/tex] 3Cu + 2AlCl3
The Attempt at a Solution
Ok. I already know that Copper Chloride is the limiting reactant, but I know how to prove it too. I have figured out the amount of Copper that would be produced from 4.00g of CuCl2 as 1.89g Cu.
I have figured out that the amount of Copper that would be produced from 25.0 g of Al as 88.3g Cu.
So, like I said... CuCl2 is the limiting reactant.
I also know that only 0.535g Al reacts with the 4.00 g of CuCl2.
But- I honestly don't get what this question is actually asking me to do... it's driving me nuts.