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jfkline21
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An electron (mass of 9.110×10-31kg and charge of -1.602×10-19C) is released at rest above the surface of the Earth (where g = 9.81 m/s2). A second electron directly below it exerts an electrostatic force on the first electron that exactly cancels the gravitational force. What is the distance between the two?
F=Eq
F=ma
F=kq1q2/r^2
I honestly don't know at all how to solve this. If someone could explain to me how and maybe show me the initial steps, that would be great!
Homework Equations
F=Eq
F=ma
F=kq1q2/r^2
The Attempt at a Solution
I honestly don't know at all how to solve this. If someone could explain to me how and maybe show me the initial steps, that would be great!