- #1
Appa
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Homework Statement
I should find this integral:
[tex]\int[/tex]b x(1/[tex]\Pi[/tex])(1/(1+x2)dx
-b
Homework Equations
[tex]\int[/tex]1/(1+x2)dx = arctan(x)
The Attempt at a Solution
The Only thing I've succeeded in doing is to take the 1/[tex]\Pi[/tex] and put it in front of the integral like this:
(1/[tex]\Pi[/tex])[tex]\int[/tex]b (x/(1+x2)dx
-b
And I know that the integral of 1/(1+x2) equals arctan(x) but how could that help me? I've tried to use the equation
[tex]\int[/tex]f(x)g(x)dx = F(x)g(x) - [tex]\int[/tex]F(x)g'(x)dx
but I can't compute the integral of arctan(x).
Could someone help me?