The initial velocity of the object can be calculated using the equation v = √(2gh), where v is the initial velocity, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the object is dropped. Plugging in the values, the initial velocity is approximately 6.26 m/s.
The final velocity of the object can be calculated using the equation v^2 = u^2 + 2gh, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and h is the height from which the object was dropped. Since the object is dropped from rest (u = 0), the final velocity is equal to the initial velocity, which is approximately 6.26 m/s.
The time it takes for the object to reach the water level can be calculated using the equation t = √(2h/g), where t is the time, h is the height from which the object is dropped, and g is the acceleration due to gravity. Plugging in the values, the time taken is approximately 0.64 seconds.
The kinetic energy of the object can be calculated using the equation KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the final velocity. Plugging in the values, the kinetic energy of the object is approximately 980 J.
The impact force of the object can be calculated using the equation F = m * a, where F is the impact force, m is the mass of the object, and a is the acceleration due to gravity. Since the object hits the water with a velocity of 6.26 m/s, the deceleration due to gravity is also 6.26 m/s^2. Therefore, the impact force is approximately 313 N.