Calculating the mass in a solenoid system

In summary, the conversation discusses the setup of two coils, one larger with 10,000 turns and one smaller with 500 turns, with electric currents of 5 A and 1 A respectively. The smaller coil is attached to a string with a weight and can rotate around a rectangular axis. To prevent the smaller coil from turning, the mass of the weight must be 2.2 kg. If there is no mass attached to the smaller coil, it will rotate due to the magnetic fields created by the two coils.
  • #1
mmoadi
157
0

Homework Statement



Through the bigger coil with N = 10,000 turns of wire and length of L = 30 cm is flowing electric current of I = 5 A. Inside the big coil we insert a smaller coil with
N(1) = 500 turns, length of L(1) = 3 cm, and a radius r = 1 cm. The electric current flowing through the small coil is I(1) = 1 A. Axis of both coils are perpendicular to one another, smaller coil is rotatable around a rectangular axis (picture!). On the edge we attach a light string with the weight. What has to be the mass of the weight so that the small coil will not turn? In which direction do the electric currents I and I1 run?

Picture: http://item.slide.com/r/1/227/i/hpQg_yax1D-i2BRLqRDiva38H-JMSI_x/ [Broken]

Homework Equations



B= (μ(0)*I*N)/ L
M= p(m)*B
r(m)= I*S*N

The Attempt at a Solution



First part: What has to be the mass of the weight so that the small coil will not turn?

M= p(m)* [((μ(0)*I*N)/ L]

M= (I(1)*π*r²*N(1)* μ(0)*I*N)/ L
M(g)= m*(L(1)/2)*g

M= M(g)
(I(1)*π*r²*N(1)* μ(0)*I*N)/ L= m*(L(1)/2)*g
m= (2*I(1)*π*r²*N(1)* μ(0)*I*N)/ (g*L*L(1))
m= 2.2 kg

Are my calculations correct?

Thank you for helping!
 
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  • #2
If there is no mass attached to the smaller coil, what will happen to the coil?
 
  • #3


I cannot verify the accuracy of your calculations without knowing the specific values for the variables. However, your approach seems correct and the equations you have used are appropriate for calculating the mass in a solenoid system. It is important to double check your units and make sure they are consistent throughout the calculation. Also, it would be helpful to provide a clear explanation of your steps and assumptions.
 

1. How do you calculate the mass in a solenoid system?

The mass in a solenoid system can be calculated using the formula M = N * μ * I * A, where N is the number of turns in the solenoid, μ is the permeability of the material, I is the current flowing through the solenoid, and A is the cross-sectional area of the solenoid.

2. What is the unit of measurement for mass in a solenoid system?

The unit of measurement for mass in a solenoid system depends on the units used for the variables in the calculation. Generally, the mass will be measured in grams (g) or kilograms (kg).

3. Can the mass in a solenoid system be negative?

No, the mass in a solenoid system cannot be negative. It is a physical quantity that represents the amount of matter in the system and therefore cannot have a negative value.

4. How does the number of turns in a solenoid affect the mass?

The number of turns in a solenoid directly affects the mass, as it is one of the variables in the mass calculation formula. The more turns in the solenoid, the greater the mass will be.

5. Are there any other factors that can affect the mass in a solenoid system?

Yes, besides the number of turns, other factors that can affect the mass in a solenoid system include the permeability of the material, the current flowing through the solenoid, and the cross-sectional area of the solenoid. These variables can all be adjusted to change the mass in the system.

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