Open Covers and Compact Sets

In summary: Intuitively this is saying that our blanket might be infinite, but we can always make a smaller one that still covers our set.
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analysis001
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Homework Statement


I'm trying to understand what compact sets are but I am having some trouble because I am having trouble understanding what open covers are. If someone could reword the following definitions to make them more understandable that would be great.

Homework Equations


Definition: Suppose (X, d) is a metric space and S[itex]\subseteq[/itex]X. We will say that the family of sets {S[itex]\alpha[/itex]}[itex]\alpha\in[/itex]A is an open cover of S if all S[itex]\alpha[/itex], [itex]\alpha\in[/itex]A, are open sets and if S[itex]\subseteq\cup_{\alpha\in A}[/itex]S[itex]\alpha[/itex].
Definition: Given an open cover {S[itex]\alpha[/itex]} of S, we will furthermore say that the family {S[itex]\beta[/itex]}[itex]\beta\in[/itex]B, is a subcover of {S[itex]\alpha[/itex]} if B[itex]\subseteq[/itex]A and {S[itex]\beta[/itex]} is an open cover of S.
Definition: Suppose (X, d) is a metric space an S[itex]\subseteq[/itex]X. We will say that S is a compact set if every open cover {S[itex]\alpha[/itex]} of S has a finite subcover.
 
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  • #2
analysis001 said:

Homework Statement


I'm trying to understand what compact sets are but I am having some trouble because I am having trouble understanding what open covers are. If someone could reword the following definitions to make them more understandable that would be great.

Homework Equations


Definition: Suppose (X, d) is a metric space and S[itex]\subseteq[/itex]X. We will say that the family of sets {S[itex]\alpha[/itex]}[itex]\alpha\in[/itex]A is an open cover of S if all S[itex]\alpha[/itex], [itex]\alpha\in[/itex]A, are open sets and if S[itex]\subseteq\cup_{\alpha\in A}[/itex]S[itex]\alpha[/itex].
Definition: Given an open cover {S[itex]\alpha[/itex]} of S, we will furthermore say that the family {S[itex]\beta[/itex]}[itex]\beta\in[/itex]B, is a subcover of {S[itex]\alpha[/itex]} if B[itex]\subseteq[/itex]A and {S[itex]\beta[/itex]} is an open cover of S.
Definition: Suppose (X, d) is a metric space an S[itex]\subseteq[/itex]X. We will say that S is a compact set if every open cover {S[itex]\alpha[/itex]} of S has a finite subcover.

Rather than completely reword the definitions, I will maybe build up to them in a (perhaps) more intuitive way.

Throughout, let ##(X,d)## be a metric space, and let ##S\subset X##.

1a) Let ##\mathcal{S}## be a finite collection of subsets of ##X## indexed by the set ##\{1,2,...,n\}##; i.e. ##\mathcal{S}=\{S_1,S_2,...,S_n\}##, where ##S_i\subset X## for ##i=1,...,n##. We say that ##\mathcal{S}## is a finite cover of ##S## if ##S\subset\cup_{i=1}^nS_i##. We say that this cover is open if ##S_i## is open in ##X## for all ##i=1,...,n##.

1b) Let ##\mathcal{S}## be a countable collection of subsets of ##X## indexed by the natural numbers; i.e. ##\mathcal{S}=\{S_1,S_2,...,S_n,...\}##, where ##S_i\subset X## for ##i\in\mathbb{N}##. We say that ##\mathcal{S}## is a countable cover of ##S## if ##S\subset\cup_{i\in\mathbb{N}}S_i##. We say that this cover is open if ##S_i## is open in ##X## for all ##i\in\mathbb{N}##.

1) Let ##\mathcal{S}## be an arbitrary collection of subsets of ##X## indexed by the set ##\mathcal{A}##; i.e. ##\mathcal{S}=\{S_\alpha\}_{\alpha\in\mathcal{A}}##, where ##S_\alpha\subset X## for ##\alpha\in\mathcal{A}##. We say that ##\mathcal{S}## is a cover of ##S## if ##S\subset\cup_{\alpha\in\mathcal{A}}S_\alpha##. We say that this cover is open if ##S_\alpha## is open in ##X## for all ##\alpha\in\mathcal{A}##.

The visual representation of what a cover is in my head is like stitching the sets in the cover into a blanket (the union) and seeing if our set is "covered" by that blanket (i.e. contained in that union). the words finite, countable, and open are just extra descriptors telling us what kind of cover we are looking at.

2) Then a family ##\mathcal{S}'## is a subcover of ##S## (relative to the cover ##\mathcal{S}##) if (i) ##\mathcal{S}'\subset\mathcal{S}## (i.e. every subset of ##X## in the family ##\mathcal{S}'## is also in the family ##\mathcal{S}##) and (ii) ##\mathcal{S}'## is a cover of ##S##.

Basically a subcover is just a smaller (in general, though not necessarily) chunk of the original blanket that still gets the blanketing job done.

3) The definition of compactness given (sometimes referred to as "covering compactness") says that a set ##S## is compact if whenever we have an arbitrary open cover ##\mathcal{S}## of ##S##, then we can find an finite open subcover ##\mathcal{S}'## (i.e. an subcover that is a finite open cover).
 

1. What is an open cover?

An open cover of a set X is a collection of open sets whose union contains X. In other words, every point in X is contained in at least one of the open sets in the cover.

2. What is a compact set?

A compact set is a set that is closed and bounded, meaning that it contains all of its limit points and is contained within a finite distance from its boundary. Intuitively, this means that a compact set is "small" in some sense.

3. What is the difference between an open cover and a covering?

An open cover is a specific type of covering, where the covering sets are open. This is important because open sets have nice properties that make them easier to work with in mathematical proofs.

4. How are open covers and compact sets related?

A set X is compact if and only if every open cover of X has a finite subcover. In other words, every open cover of X can be "reduced" to a finite open cover that still covers X. This is one way that compact sets can be characterized.

5. Why are open covers and compact sets important in topology?

Open covers and compact sets are foundational concepts in topology, which is the study of abstract spaces and their properties. These concepts are important because they allow us to define and understand important properties of spaces, such as continuity, connectedness, and compactness.

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