Calculating Surface area/volume from 2D cross section?

In summary, the conversation discusses the concept of using a solid of revolution to calculate the surface area and volume of a radially-symmetric 3D object. It is suggested that the object can be treated as a cross-section of a simple cylinder with the same surface area. However, it is later proven to be incorrect through a counterexample involving sine and cosine functions. The conversation concludes with the realization that intuition is not always a reliable guide and that finding a counterexample can sometimes be faster than finding a proof.
  • #1
SuperG
5
0
Calculating Surface area/volume from 2D cross section??

I'm feeling a little stupid today and I need some help...:tongue2:
Assume that I have a radially-symmetric 3D object (for example a candle stick or the base of a table lamp) and that I can calculate the surface area of the largest longitudinal cross section (ie, I split the object precisely along the axis of radial symmety and measure the area of the newly exposed surface). Also assume that the outside profile of this object can be described by a function (though I do not know what the function is)
Is there any reason that I cannot then treat this object as the cross section of a simple cylinder, the product of whose length and diameter is equal to my object's cross sectional surface? In other words, if my object's cross sectional area turned out to be 10 square units with a length of 5), then can I say that my object's volume is equal to the volume of a cylinder with length 5 and diameter 2?
EDIT: corrected an error
 
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  • #2
You're talking about a solid of revolution. In that case, take note of two different SORs, one cross-section has 2 unit circles each 1 unit symmetrically from the axis, and the other of 2 unit circles each 2 units symmetrically from the axis. The resulting torii have different volumes, but the same cross-sectional area.
For objects which have the axis running through them, consider the unit circle and a square with sides of length [itex]\sqrt{\pi}[/itex]. Then the volume of their SORs are [itex]\frac{4\pi}{3}[/itex] and [itex]\frac{\pi^2\sqrt{\pi}}{2}[/itex] even though their cross-sectional areas were the same.
Also, for cross-sections of equal height and area, consider the absolute values of sine and cosine rotated.
 
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  • #3
hypermorphism said:
You're talking about a solid of revolution. In that case, take note of two different SORs, one cross-section has 2 unit circles each 1 unit symmetrically from the axis, and the other of 2 unit circles each 2 units symmetrically from the axis. The resulting torii have different volumes, but the same cross-sectional area.

Assuming no hollow center though, would my method work?

I understand that what I'm assuming would not be universally applicable, but may rather be a special case.

I'm going to work on it some more to at least understand where this method fails (FWIW, this is not a class assignment but rather an applied problem--I'm trying to save my lab $3000)

Thanks for your comments
 
  • #4
Hi Super,
See the rest of my reply.
 
  • #5
On my drive home I convinced myself that my method is correct (even if my explanation may not have been very good :smile: )

I convinced myself with the following analogy. Imagine that the object in question--lets say it's a turned chair leg with lots of nice curves and a constantly changing diameter--is made not out of wood but out of something like an uncompressible yet malleable clay.
Constraining its longitudinal dimension, it then stands to reason that that chair leg can be reformed into one and only one solid cylinder. The longitudinal cross section of that cylinder will then have an area which is, of course, symmetric around the chair leg's long axis. Obviously this area must then be the same as the area of the chair leg's longitudinal cross section. Therefore, if I can measure (or estimate) the area of the chair leg's longitudinal cross section-because maybe, all I have is a 2D image of the chair leg-I can then come up with a corresponding cylinder (again, holding length constant) which has the same longitudinal cross sectional area and hence, derive a volume for the leg.

Which of course gets me nowhere :rolleyes: because I want to ultimately figure out the surface area of the leg, not the volume. :rofl:

Oh well, at least my drive home wasn't boring :smile:
 
  • #6
The sine and cosine counterexample proves the stated hypothesis wrong, unless you refine the hypothesis further.
 
  • #7
I'm afraid I see that you are correct.

Just shows that intuition is no match for actually crunching some numbers...

Thanks for the coaxing.
 
  • #8
No problem. There are a lot of hypotheses that seem like they should be true because they hold for a large amount of examples, but turn out to be false.
 
  • #9
So how did you see that this was incorrect so quickly? Had you seen this balloon floated before?
 
  • #10
I actually didn't see that it was incorrect at first, but I did look for a counterexample. If a nontrivial statement is false, one is sometimes able to find a counterexample faster than finding a proof if a statement is true (ie., why proof by contradiction is so satisfying). If I couldn't find a counterexample, I would've started to see how one would prove it.
I also thought it strange that if it was true, I had never seen it as a cute problem in any of my myriad analysis texts. :smile:
 
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1. How do I calculate the surface area from a 2D cross section?

To calculate the surface area, you will need to use the formula for the surface area of the 3D shape that the 2D cross section represents. For example, if the 2D cross section is a circle, you would use the formula for the surface area of a sphere. If the 2D cross section is a rectangle, you would use the formula for the surface area of a cuboid.

2. What units should I use when calculating the surface area?

The units you use for the surface area will depend on the units used in the formula for the 3D shape. For example, if the formula requires length in meters, then the surface area will be in square meters. Make sure to use consistent units throughout your calculations.

3. How do I find the volume from a 2D cross section?

To find the volume, you will need to use the formula for the volume of the 3D shape that the 2D cross section represents. This formula will typically involve the length, width, and height of the shape. For example, if the 2D cross section is a triangle, you would use the formula for the volume of a pyramid.

4. Can I use a different shape to calculate the surface area or volume?

Yes, you can use any shape to calculate the surface area or volume as long as you use the correct formula for that shape. Keep in mind that the 2D cross section should accurately represent the shape of the 3D object.

5. How accurate will my calculated surface area or volume be?

The accuracy of your calculation will depend on the accuracy of your measurements and the precision of your calculations. Make sure to use precise measurements and double check your calculations to ensure the most accurate results.

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