- #1
Kalie
- 46
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Torque? Rotation it has the Word Pivot...
A forearm can be modeled as a 2.50 kg, 32-cm-long "beam" that pivots at the elbow and is supported by the biceps.
http://session.masteringphysics.com/problemAsset/1001007/10/knight_Figure_13_58.jpg
How much force must the biceps exert to hold a 430 g ball with the forearm parallel to the floor?
Okay So I have no clue how to aproach. I'm thinking torque=rFsin theta and solve for F...but I don't knwo how to do that
Anyone want to give me a small clue to start this?
Oh yeah when you look at the picture is r=2.5 cm...?
Thanks
A forearm can be modeled as a 2.50 kg, 32-cm-long "beam" that pivots at the elbow and is supported by the biceps.
http://session.masteringphysics.com/problemAsset/1001007/10/knight_Figure_13_58.jpg
How much force must the biceps exert to hold a 430 g ball with the forearm parallel to the floor?
Okay So I have no clue how to aproach. I'm thinking torque=rFsin theta and solve for F...but I don't knwo how to do that
Anyone want to give me a small clue to start this?
Oh yeah when you look at the picture is r=2.5 cm...?
Thanks