Photoelectric effect electron angular distribution

[Perion]

With respect to the photoelectric effect conservation of momentum, it is clear that the lattice plays a major role, and therefore the outgoing electron doesn't necessarily follows the photon's direction of incidence. However, the photon's direction of incidence plays some role in shaping the angular distribution of the outgoing electrons.
I would appreciate if someone could comment (quantitatively) on how the direction of incidence of a beam of photons on a flat thin metal plate affects the angular distribution of the outgoing electrons.
Thanks.

 

[BigJDubs]

The direction of incidence of a beam of photons on a flat thin metal plate affects the angular distribution of the outgoing electrons in two ways. First, it determines the direction of the momentum transfer. The momentum transfer is the difference between the momentum of the incident photons and the momentum of the outgoing electrons. Since the electrons are ejected from the metal surface in all directions, the direction of the momentum transfer will determine the angle of the electrons relative to the incident photon direction. Second, it determines the probability of the photoelectric effect occurring at each point on the metal surface. For example, when a photon is incident perpendicular to the surface, the probability of the photoelectric effect occurring is higher than if the photon is incident at an angle. This is because the electric field of the photon is strongest when it is perpendicular to the surface, allowing for more efficient transfer of energy. As a result, the angular distribution of the outgoing electrons is affected by the direction of incidence of the beam of photons.