- #1
touqra
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The Ampere's Law is [tex] \nabla \times B = \mu J [/tex] and Gauss's Law is [tex] \nabla \cdot E = \frac{1}{\epsilon} \rho [/tex]
Since J is current density, is it right to say that, [tex] J = \frac{d}{dt} \rho [/tex] in general?
I am abit confused, since I know that a current four-vector, [tex] (\rho , J) [/tex] is similar to a spacetime four-vector [tex] (t, x) [/tex]. But, x is not [tex] \frac{d}{dt} t [/tex]
Also, does a non-zero J automatically implies a non-zero [tex] \rho [/tex] ?
Since J is current density, is it right to say that, [tex] J = \frac{d}{dt} \rho [/tex] in general?
I am abit confused, since I know that a current four-vector, [tex] (\rho , J) [/tex] is similar to a spacetime four-vector [tex] (t, x) [/tex]. But, x is not [tex] \frac{d}{dt} t [/tex]
Also, does a non-zero J automatically implies a non-zero [tex] \rho [/tex] ?