- #1
yaho8888
- 62
- 0
Homework Statement
A skier starts from rest at the top of a 26 degree slope 1.3Km long.
how long does it take to reach the bottom? (no friction)
The attempt at a solution
m=mass
m*g*sin(24) = ma(at slope direction)
divide both side by m
we got
g*sin(24)=a
then use
v^2(final) = V^2(initial)+2(9.8m/s^2)(sin(24))(1300m)
V^2(final) = 0+2(9.8m/s^2)(sin(24))(1300m) we know that initial v is zero.
we get V from the equation above.
then use
v= v(initial)+at
v=0+(9.8m/s^2)sin(24)t
t=V/9.8sin(24).
done!