How Does Pascal's Principle Apply in Hydraulic Systems?

[chukie]

Homework Statement

A 200 kg object sits on a 3.0 m2 piston that is connected to a hydraulic system with a 0.5 m2 piston attached. What is the pressure under the 3.0 m2 piston? What is the pressure under the 0.5m2 piston and why? What force needs to be applied to the smaller piston to move the object?

The Attempt at a Solution

For the pressure under the 3.0 m2 piston. I used P=F/A
P=(200*9.8)/3
P=653 Pa

Is this rite? or should i use 3.0+0.5 for A?

for the other pressure i said it was the same because of Pascal's principle.

As for the last part i did F1A1=F2A2
so F2=(F1A1)/A2
F2=(200*9.8*0.5)/3
=327N

I'm not sure if i did this right. any help/comment would help a lot.

 

[Hootenanny]

Homework Statement

A 200 kg object sits on a 3.0 m2 piston that is connected to a hydraulic system with a 0.5 m2 piston attached. What is the pressure under the 3.0 m2 piston? What is the pressure under the 0.5m2 piston and why? What force needs to be applied to the smaller piston to move the object?

The Attempt at a Solution

For the pressure under the 3.0 m2 piston. I used P=F/A
P=(200*9.8)/3
P=653 Pa

Is this rite? or should i use 3.0+0.5 for A?

for the other pressure i said it was the same because of Pascal's principle.

As for the last part i did F1A1=F2A2
so F2=(F1A1)/A2
F2=(200*9.8*0.5)/3
=327N

I'm not sure if i did this right. any help/comment would help a lot.

Looks good to me

 

[Moetasim]

I would like to clarify that the calculation of pressure under the 3.0 m2 piston is correct, assuming that the force acting on the piston is only due to the weight of the object. However, it is important to note that the pressure under a piston in a hydraulic system is dependent on the force acting on the smaller piston, not just the weight of the object. Therefore, the pressure under the 3.0 m2 piston may change if a force is applied to the smaller piston.

For the pressure under the 0.5 m2 piston, it is indeed the same as under the 3.0 m2 piston due to Pascal's principle, which states that pressure is transmitted equally throughout a confined fluid.

Your calculation of the force needed to move the object using the equation F1A1 = F2A2 is also correct. However, it is important to consider the direction of the force. In this case, a downward force needs to be applied to the smaller piston to lift the 200 kg object. Therefore, the force needed would be negative (-327 N).