Calculate the maximum height that m1 and m2 rise after collision?

In summary, the problem involves a frictionless track with three sections, a quarter circle from A to B, a horizontal flat plane from B to C, and another quarter circle from C to D. An object with a mass of 2kg is released from A and makes a head-on elastic collision with another object of mass 10kg at B. The radius of the quarter circles is 4.9m. The maximum height to which the objects will rise after the collision needs to be calculated. This can be done by finding the velocity of the first object after it falls through the quarter circle A to B and using conservation of momentum to calculate the final velocities of both objects after the collision.
  • #1
kalisious
13
0

Homework Statement


Consider a frictionless track. Imagine point A to B is one quarter of a circle; point B to C is a horizontal flat plane; point C to D is also one quarter of a circle.

The block m1 is released from A. It makes a head-on elastic collision at B with m2 (that is initially at rest) Calculate the maximum height to which m1 and m2 rise after collision.

m1 = 2kg
m2 = 10 kg
radius of quarter circles = 4.9 m


Homework Equations


p=mv

m1vf + m2vi = (m1 + m2)v

y=1/2 at^2


The Attempt at a Solution


I am not quite sure how to attempt a solution.
 
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  • #2
Can you find out how fast m1 is going after it falls through the quarter of a circle A to B? Then you could do conservation of momentum on the collision at B.
 
  • #3
I understand the equation for conservation of momentum, but how do I go about finding the velocity as you mentioned?
 
  • #4
Draw the diagram. You should see how high above the BC horizontal section m1 is initially. From the initial height, you can calculate its speed after falling through the height either by using forces or energies.
 

1. What is the equation used to calculate the maximum height of m1 and m2 after collision?

The equation used to calculate the maximum height of m1 and m2 after collision is h = (m1*v1^2 + m2*v2^2)/(2*(m1+m2)*g), where h is the maximum height, m1 and m2 are the masses of the objects, v1 and v2 are the initial velocities of the objects, and g is the acceleration due to gravity (9.8 m/s^2).

2. Can the maximum height of m1 and m2 be negative?

No, the maximum height of m1 and m2 cannot be negative. The equation for calculating maximum height includes squared values, which will always result in a positive value. Additionally, the height of an object cannot be negative in a physical sense.

3. What are the units for the maximum height calculation?

The units for the maximum height calculation will depend on the units used for mass and velocity. In the metric system, the units for mass are typically kilograms (kg) and the units for velocity are meters per second (m/s), resulting in the units for maximum height being meters (m). In the imperial system, the units for mass are typically pounds (lbs) and the units for velocity are feet per second (ft/s), resulting in the units for maximum height being feet (ft).

4. How does the angle of collision affect the maximum height of m1 and m2?

The angle of collision does not directly affect the maximum height of m1 and m2. However, it can affect the initial velocities of the objects, which will then impact the maximum height calculation. For example, if the objects collide at an angle, the initial velocities in the x and y directions will be different, resulting in different maximum heights in those directions.

5. Is air resistance taken into account in the maximum height calculation?

No, the maximum height calculation assumes that there is no air resistance. In real-world scenarios, air resistance will affect the maximum height of objects in motion, but for this calculation, it is not taken into account. This assumption is made to simplify the calculation and provide a theoretical maximum height.

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