Fourier Transform of Differential Equation

Yes, that looks right. Keep going!Well, I'm feeling pretty confident with that now!So I have:\frac{\partial^{3}u}{\partial x^{3}} + 2 \left( \frac{\partial u}{\partial x} \right) = \frac{\partial u}{\partial t}LHS:F\left[\frac{\partial^{3}u}{\partial x^{3}}\right] + 2F\left[\frac{\partial u}{\partial x}\right] = (ik)^{3}F[u] + 2ikF[u] = \left(ik^{3} + 2ik\right)F
  • #36
.. indeed it is! :biggrin:
 
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  • #37
.. any pointers for finding A(k) for the case where u(x,t) at t=0 is given by:

[tex] u(x,0) = U_{0}\delta (x-a) [/tex] where Uo is a constant ?!?
 

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