Stoichiometry hydrated NiSO4 question

In summary: JohnRC. In summary, by heating a 40.14g sample of hydrated NiSO4 and observing a decrease in mass to 22.14g, it can be shown that the formula of the hydrate is NiSO4.7H2O. Through stoichiometric calculations, a ratio of 1:6.982 was determined, leading to the empirical formula of NiSO4.7H2O. Similarly, a 139.4g sample of hydrated MnSO4 reduced to 94.38g upon heating, resulting in an empirical formula of MnSO4.4H2O. The name of the hydrate is Manganese (II) sulfate tetrahydrate.
  • #1
5ymmetrica1
88
0

Homework Statement



given that 40.14g sample of hydrated NiSO4 is reduced in mass to 22.14g upon heating.
Show that the formula of the hydrate is NiSO4.7H20

Homework Equations



n / M

The Attempt at a Solution



22.14g/ 40.14g = 0.5516 (mol of NiSO4)

40.14g - 22.14 = (18 g H20 lost in heating)

18.0 / 18.02 = 0.9989 (mol of H20)

∴ mole ratio = 0.5516 : 0.9989

but this does not give the result in the ratios of 1:7 (NiSO4.7H20)stoichiometry (or chem for that matter) isn't really my thing and I have about 10 questions similar to this, can someone please point me in the right direction please?
 
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  • #2
22.14/ 150.76 = 0.1469 (mols of NiSO4)

0.1469:0.9989
1.469:9.989 (x10)

which is a ratio of 1:6.79

but is there a more accurate way of calculating this?
 
  • #3
Your second calculation is much better than the first. Have another try at calculating the molar mass of NiSO4. 150.76 g/mol is wrong.
 
  • #4
thanks for the tip johnRC, I needed to check my copy of the periodic table better!

does this calculation look more correct? the ratios are almost perfect, which my chem teacher has said is to be expected.

22.14 / 154.76 = 0.14306 (mols of NiSO4)
40.14g - 22.14 = 18.00 (H20 lost in heating)
18.0 / 18.02 = 0.9989 (mols of H20)
0.14306:0.9989
0.14306/0.9989 = 0.1432
1/0.1432 = 6.982

1:6.982
6.98 ≈ 7
∴ NiSO4.7H2O
 
  • #5
Right on, symmetrica1!
 
  • #6
thanks john!

could anyone take a look at this for me please?

Given that a 139.4g sample of hydrated MnSO4 is reduced in mass to 94.38g upon heating, find the empirical formula of the Hydrate. Also, write the name of the hydrate of manganese sulphate.

94.38g / 151g = 0.6250 (mols of MnSO4)
139.4g – 94.38g = 45.02g (H2O lost in heating)
45.02 / 18.02 = 2.4983 (mols of H2O)

0.6250:2.4983
0.6250/2.4983 = 0.250166
1 / 0.250166 = 3.997

1:3.997
3.997 ≈ 4
∴ MnSO4.4H2O

would the name of the hydrate be Manganese (II) sulfate monohydrate?
 
Last edited:
  • #7
5ymmetrica1 said:
MnSO4.4H2O

Yes.

would the name of the hydrate be Manganese (II) sulfate monohydrate?

No.

Mono means one, not four.

Please start new threads if you have new questions.
 
  • #8
sorry borek, I thought it would come under the same topic heading anyway so was just trying to keep your forums neat. Will do in future posts

thanks for checking my answer
 

1. What is stoichiometry?

Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction.

2. What is hydrated NiSO4?

Hydrated NiSO4 is the chemical formula for nickel sulfate, which is a compound containing nickel, sulfur, and oxygen atoms. The "hydrated" part of the name indicates that the compound contains water molecules in its chemical structure.

3. How do you calculate the number of moles in a given amount of hydrated NiSO4?

To calculate the number of moles in a given amount of hydrated NiSO4, you need to know the molar mass of the compound and the amount of the compound in grams. Then, you can use the formula moles = mass/molar mass to find the number of moles.

4. What is the purpose of stoichiometry in chemistry?

The purpose of stoichiometry in chemistry is to determine the quantities of reactants and products involved in a chemical reaction. This information is important for predicting the outcome of a reaction and for designing and optimizing chemical processes.

5. How does stoichiometry relate to hydrated NiSO4?

Stoichiometry is used to determine the quantities of reactants and products in a chemical reaction, including hydrated NiSO4. It can be used to calculate the amount of hydrated NiSO4 needed for a reaction or the amount of products that will be formed from a given amount of hydrated NiSO4.

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