- #1
Bipolarity
- 776
- 2
The invertible matrix equation tells us that the following statements are equivalent, for any square matrix A:
1) A is invertible
2) Ax=0 has only the trivial solution
3) Ax=b has a unique solution for any column vector b
My question:
Suppose you know that A is a singular matrix. Then can you conclude that for every column vector b, either Ax=b has no solution or Ax=b has infinitely many solutions? Or is there a vector b for which Ax=b has a unique solution, despite the fact that A is singular?
Also, given that A is singular, how can you tell whether Ax=b has no solutions or has infinitely many solutions?
BiP
1) A is invertible
2) Ax=0 has only the trivial solution
3) Ax=b has a unique solution for any column vector b
My question:
Suppose you know that A is a singular matrix. Then can you conclude that for every column vector b, either Ax=b has no solution or Ax=b has infinitely many solutions? Or is there a vector b for which Ax=b has a unique solution, despite the fact that A is singular?
Also, given that A is singular, how can you tell whether Ax=b has no solutions or has infinitely many solutions?
BiP