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Simulation of ppcollision and Z boson productionby Jan Eysermans
Tags: boson, center of mass, collider beams, partons, ppcollision, production, quarks, simulation 
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#19
Dec1313, 07:40 AM

P: 85

This looks good to me. What energy collisions, LHC collisions?
Both x1 and x2 must always be in the range 01 to avoid violating the momentum sum rules. (the quark cant have more energy than its mother hadron). If this is now working, hopefully it can help you to calculate whatever it is you want to calculate. 


#20
Dec1313, 08:13 AM

P: 17

Yes, p = 4000 GeV, or LHC collisions. Here is an image of the uPDF, randomly chosen over 1E6 times: http://postimg.org/image/zc6xga97n
It is most likely to produce an x1 value smaller then 10E1, 1E2. The correspondig x2 values are then always > 1. Maybe I have to force x2 to be smaller than 1, which implies a constraint on x1: [itex]x_2 = \frac{m_Z^2}{4p^2x_1} \leq 1 \Rightarrow x_1 \geq \frac{m_Z^2}{4p^2} [/itex] If x1 is too small, it has not enough energy (even with a 4000 GeV quark) to produce a Z boson. Can this be correct? 


#21
Dec1313, 08:22 AM

P: 85

Okay nice, the image looks like everything is working.
So I tried a little example. x1 = 1e2 for the up quark. {i.e. 40 GeV for 4TeV collisions} x2 p = Mz^2 / 4 x1 p x2 p = {91.8}^2/ {4 * 1e2 4000 } x2 p = 52 GeV x2 = 52/4000 = 0.01316 for the antiup. Does this agree with the code? 


#22
Dec1313, 08:59 AM

P: 17

Yes indeed, that is exactly the result here from my program. One last question about the randomness. Now, I sample always from the uPDF distribution. But, off course, it is also possible to sample from the antiu PDFs. I guess it is important to incorporate both PDFs?



#23
Dec1313, 09:08 AM

P: 85

Great! Because in this case we have a fixed invariant mass ( the Mz ) by samplying the uPDF you are simultaneously sampling the ubar since there is only one solution.
I *guess* in practice, one should scan over the entire x1range. For each point in x1, in this case there is only 1 viable x2, so multiplying these two together gives you the flux. If you were generating Zjets, or off shell Z's, I think what you have to do is integrate over the entire x2range of values for each x1 piece. Which is alot more computer intensive.. I think the MonteCarlo programs which do event generation do not do this, but have clever ways to improve efficiency. Maybe someone else knows about this. good luck! 


#24
Dec1313, 10:00 AM

P: 17

Yes, indeed. Thank you for the answers!
Jan 


#25
Dec1313, 06:58 PM

Mentor
P: 11,888

Don't forget the other quarks, however. 


#26
Dec1413, 02:42 AM

P: 17

The other quarks are incorporated by weighting over all the PDFs. 


#27
Dec1413, 04:01 AM

P: 85

You should get two different answers. Because of the valence content of the proton. If you compared s, c, b to sbar cbar bbar you expect a symmetry.
Presumably just means interchange of x1 x2 labels to the quark or anti quark 


#28
Dec1413, 04:50 AM

P: 17

Is there any statistical procedure to incorporate all the distributions for selecting the x1? 


#29
Dec1413, 05:18 AM

P: 85

For your procedure of producing the Z on shell. It is correct to only sample the uPDF in my opinion. You automatically sample all possibilities at the same time here.
My guess is that when you find a suitable solution of x1 and x2. i.e. one where you get the z mass you can store these x1' values, then calculate the sum of, u ubar @ x1' d dbar @ x1' s sbar @ x1' c cbar @ x1' b bbar @ x1' If you want to make things more detailed etc. that is always possible. In event generators, I think the hard process is sampled first, then evolution back to the parton distribution function is done. This way you don't have to veto lots and lots of processes which don't give you the right energy exchange to produce the Z {though you are sort of doing this by forcing Z on shell}. But at this point I think you may need to consult publications and text books  my normal approach is to look here first, http://books.google.co.uk/books/abou...UC&redir_esc=y or search online to try and find something useful. 


#30
Dec1413, 06:36 AM

P: 17

Your explanation was for improving the error on handling the PDFs at q = M_z, right? What I mean is the difference between selecting x1 out of the quarkdistributions or the antiquarkdistributions.
To make things clear, let say we want to produce an onshell Z boson from u and d quarks (and the antiquarks). Now, my algorithm is the following: 1. select x1 out of (u+d)PDF @ q = M_z 2. calculate x2 3. calculate p_Z = (x1x2)*p, and calculate, for example, the boost parameter beta 4. plot beta in an histogram When I repeat this algorithm, but changing step 1 into selecting x1 out of (antiu + antid)PDF at q= M_Z, I get a slightly different result. In my opinion, I have to incorporate both u+d and antiu+antid PDFs for generating the x1 value. Thanks again! Jan 


#31
Dec1413, 09:17 AM

Mentor
P: 16,352

This isn't going to work. That procedure forces x2 to have a particular distribution, and that distribution may or may not (in fact, doesn't) match the correct x2 distribution.
What you need to do instead, if you want to go down this path, is once you have the x2, you calculate the probability of getting this x2, and then toss a random number. If the random number matches this probability, you keep the event, otherwise, you start over. This is called reweighting. 


#32
Dec1413, 10:23 AM

Mentor
P: 11,888

I don't see how sampling the uPDF covers processes like antis + s > Z. I agree with Vanadium in terms of reweighting. 


#33
Dec1413, 01:07 PM

P: 17

Indeed, including the distributions for x2 are needed.. I have implemented the method of Vanadium 50 and the results are more or less ok! Thanks everyone.



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