Why is free body diagram named as such?

In summary, when creating a free body diagram, you only consider the forces acting on the chosen body. In the case of a lift, the man's force on the lift (or lift floor) should be included in the free body diagram of the lift, while the lift's force on the man should be included in the free body diagram of the man. The apparent weight of the man should be used in equations for the lift floor, rather than his actual weight. It is up to the individual to choose the most appropriate body for the free body diagram, usually based on the forces involved in the problem.
  • #1
manjuvenamma
102
0
Let us consider a lift which is moving with a constant acceleration with a man inside. Now we know that the man exerts a force which is different from his weight depending on the direction of the movement. Now, when we consider the free body diagram of the lift do we take into consideration the force applied by the man on the lift (actually lift floor) and the force applied by the lift floor on the man? What are the guidelines for resolution of this kind of questions while writing the free body diagram.

Why is free body diagram named as such? A body in general is acted upon by a few forces and thus is not free.
 
Physics news on Phys.org
  • #2
manjuvenamma said:
Now, when we consider the free body diagram of the lift

(I added the emphasis here)

do we take into consideration the force applied by the man on the lift (actually lift floor)

Yes.

and the force applied by the lift floor on the man?

No.

In a free-body diagram you consider one object at a time, and you include only those forces that are exerted on that object. If you are doing a free-body diagram of the lift, you include the forces that are exerted on the lift, including the force exerted by the man on the lift. If you are doing a free-body diagram of the man, you include the forces that are exerted on the man, including the force exerted by the lift on the man.

The force exerted by the man on the lift and the force exerted by the lift on the man are equal in magnitude and opposite in direction, according to Newton's Third Law.
 
  • #3
Thanks for the clarification.

Can you draw free diagram of the floor of the lift? The man is applying his apparent weight on the floor and the floor of the lift is moving (say up) with a constant acceleration. So there must be net force up on the floor of the lift. This upward force on the floor lift should be equal to the force applied by the man on the lift floor plus the mass of the lfit floor X acceleration.

Is it coorect to apply free body diagram for a part of the body (such as floor the lift)
 
  • #4
You can choose anything--or part of anything--as your "body" for the purposes of drawing a free-body diagram. But for any given problem, there is usually one obvious choice that makes the most sense. (Although it might not be so obvious at first. :wink:)

If you have the choice, for this situation I would pick the man as your "body" and do a free body diagram showing all the forces on him. (If you pick the elevator, you'll need to consider all forces acting on the elevator. Are you given information about those forces?)

It all depends on what you are asked to find.
 
  • #5
As mentioned by others, it is up to you to choose where to draw the lines that define your free body. You can draw that line anywhere you wish, and you only consider forces that cross the line. Usually, you want to look at the question and draw a body that has the force you are interested in, and as few other forces as possible.
 
  • #6
To reconfirm, in this situation of lift floor, what will be the equation from free body diagram? Is the below eqn. correct, or did I miss something?

Net force on lift floor = lift floor mass X acceleration = Apparent weight of man + lift floor weight.

Thanks for the help.
 
  • #7
No, I think the equation can not be correct. Is the below one correct?

Net force on lift floor = lift floor mass X acceleration = Upward pull force - (Apparent weight of man + lift floor weight).
 
  • #8
My specific point in this equation is, do we take the weight of man or the apparent weight of man in the above equation? I think apparent one we should consider since that is what the man applies on the floor.
 
  • #9
You are correct, it is the apparent weight of the man. The weight of the man is the force of gravity and it acts on the man. Since that force acts on the man it is acting on a different body than the lift floor. The apparent weight of the man is the force that he exerts on the floor.
 

1. Why is it called a "free" body diagram?

A free body diagram is called as such because it represents a body that is free from its surroundings or external forces. Therefore, all the forces acting on the body are shown as separate and isolated vectors on the diagram.

2. What is the purpose of a free body diagram?

A free body diagram is used to visually represent the different forces acting on a body in a given situation. It helps to analyze and understand the forces acting on the body and their effects, which can be used to solve problems and make predictions.

3. How is a free body diagram different from other types of diagrams?

A free body diagram only includes the forces acting on a single body, while other types of diagrams may include multiple bodies or other information such as velocity or acceleration. Additionally, the forces on a free body diagram are shown as isolated vectors, rather than in a specific direction or orientation.

4. Can a free body diagram be used for any type of object?

Yes, a free body diagram can be used for any type of object, whether it is a solid, liquid, or gas. It can also be used for non-physical systems such as mathematical models.

5. Why is it important to draw a free body diagram accurately?

Drawing a free body diagram accurately is crucial for understanding and solving problems involving forces. Any error in the diagram can lead to incorrect analysis and predictions. Therefore, it is important to pay close attention to the direction and magnitude of the forces represented on the diagram.

Similar threads

Replies
8
Views
1K
Replies
31
Views
3K
Replies
14
Views
2K
Replies
6
Views
2K
Replies
2
Views
1K
Replies
3
Views
3K
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
443
Back
Top