- #1
Punjabi.Sher
- 7
- 0
A gas contains a mixture of He and Ne.
The gas is at a temperature of 448 K, with
0.85 mole of He and 2 mole of Ne.
Avogadro’s number is 6.02 × 1023 mol−1,
and Boltzmann’s constant is 1.38×10−23 J/K.
What is the average kinetic energy per
molecule of He? Answer in units of J.
2. KE(bar) = (1/2)mv² = (3/2)kT
3. The middle equation above gives you the average kinetic energy, but I don't have any velocity. Can someone please guide me with this problem?
The gas is at a temperature of 448 K, with
0.85 mole of He and 2 mole of Ne.
Avogadro’s number is 6.02 × 1023 mol−1,
and Boltzmann’s constant is 1.38×10−23 J/K.
What is the average kinetic energy per
molecule of He? Answer in units of J.
2. KE(bar) = (1/2)mv² = (3/2)kT
3. The middle equation above gives you the average kinetic energy, but I don't have any velocity. Can someone please guide me with this problem?