- #1
zn5252
- 72
- 0
hello,
please see the attached snapshot (taken from 'Problem book in relativity and gravitation'). In the last equation I think there would be no semicolon.
Here is why I believe (S is scalar by the way):
S;α[βγ] = 1/2 * ( S;αβγ - S;αγβ )
Now from the equation which precedes it, we have :
S;αβγ = S,αβγ - Sσ τ σ αβ,γ
and :
S;αγβ = S,αγβ - Sσ τ σ αγ,β
this means :
S;α[βγ] = 1/2 * ( Sσ Rσαβγ ) due to the first equation of the solution 9.8 on the top of the page.
We see that there is no semicolon. Where did I go wrong if at all ?
Thank you,
please see the attached snapshot (taken from 'Problem book in relativity and gravitation'). In the last equation I think there would be no semicolon.
Here is why I believe (S is scalar by the way):
S;α[βγ] = 1/2 * ( S;αβγ - S;αγβ )
Now from the equation which precedes it, we have :
S;αβγ = S,αβγ - Sσ τ σ αβ,γ
and :
S;αγβ = S,αγβ - Sσ τ σ αγ,β
this means :
S;α[βγ] = 1/2 * ( Sσ Rσαβγ ) due to the first equation of the solution 9.8 on the top of the page.
We see that there is no semicolon. Where did I go wrong if at all ?
Thank you,