Calculate induced emf across loop antenna by another loop antenna

[avionion]

Homework Statement

i need to find emf across 50 ohm load attached to square loop antenna of single turn with each side of 10 cm. this antenna is placed 10 cm away from a similar antenna which is driven by a sinusoidal source of 10 v amplitude and with 1mW power.

Homework Equations

i have derived E field equation of loop with sinusoidal source but don't know how can i get flux or H through the second loop to measure emf,
V= 2pi*u*N*A*f*H*cos(theta)
B=uH

The Attempt at a Solution

 

[Jhero]

To find the emf across the 50 ohm load, you will need to calculate the flux through the second loop. This can be done by using Faraday's law, which states that the emf induced in a loop is equal to the rate of change of flux through the loop. In this case, the loop is the 50 ohm load and the flux is the magnetic flux through the loop caused by the nearby antenna.

To calculate the magnetic flux, you will need to use the equation B=uH, where B is the magnetic field, u is the permeability of the medium (in this case, air), and H is the magnetic field strength. You can calculate H using the equation you have derived for the E field of the first loop. Once you have calculated the magnetic flux, you can then use Faraday's law to calculate the emf across the 50 ohm load.

Alternatively, you can also use the equation V= 2pi*u*N*A*f*H*cos(theta) to calculate the emf directly, where N is the number of turns in the second loop, A is the area of the loop, f is the frequency of the sinusoidal source, H is the magnetic field strength, and theta is the angle between the plane of the loop and the direction of the magnetic field.

To get a more accurate measurement of the emf, you may also need to take into account the impedance of the antenna and the transmission line connecting the two antennas. This can be done by using the equations for impedance matching.

I hope this helps you in finding the emf across the 50 ohm load. Good luck with your calculations!