- #1
Hotsuma
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Hello all,
I am trying to work on some Ring Theory proofs and my Abstract Algebra is very minimal as I have not taken the class but need to look into it nonetheless. If anyone can figure these out for me I'd greatly appreciate it.
Also, I am familiar in LaTeX typesetting but I don't know how to fluidly use it on this forum. If I enable the TeX can I use my typical math commands and implement conventional TeX'ing?
This is the doozy for me:
If R1,R2,...,Rn are commutative rings with identity, shows that U (R1 x R2 x ... x Rn) = U(R1) x U(R2) x ... x U(Rn)
Identity: There exists some 1 in R such that a*1 = 1*a = a
Commutativity: A, b in R such that ab = ba for all a, b.
Unit: Must have identity, there exist some y in R such that xy = yx =1. Must be commutative.
I've tried all sorts of debauchery but nothing seems to work. I have tried splitting this up and looking at it different ways, but nothing I've come up with is correct.
Show that a finite commutative ring with no zero-divisors and at least two elements has identity.
See above.
So I need to show it is finite (easy), commutative, no zero-divisors, and and at least two elements has identity.
I define some ring R with no zero-divisors and at least two elements. Let a,b be in R. There exists a*a=1; a*b= a (or b). If a*a=a, then a*a*b=a*b...
Here I just keep running in circles.
Prove that (x) in Q[x] is maximal.
Q is the set of all rationals.
http://en.wikipedia.org/wiki/Maximal_element"
Nothing. =[
Thank you for all the help!
I am trying to work on some Ring Theory proofs and my Abstract Algebra is very minimal as I have not taken the class but need to look into it nonetheless. If anyone can figure these out for me I'd greatly appreciate it.
Also, I am familiar in LaTeX typesetting but I don't know how to fluidly use it on this forum. If I enable the TeX can I use my typical math commands and implement conventional TeX'ing?
Homework Statement
This is the doozy for me:
If R1,R2,...,Rn are commutative rings with identity, shows that U (R1 x R2 x ... x Rn) = U(R1) x U(R2) x ... x U(Rn)
Homework Equations
Identity: There exists some 1 in R such that a*1 = 1*a = a
Commutativity: A, b in R such that ab = ba for all a, b.
Unit: Must have identity, there exist some y in R such that xy = yx =1. Must be commutative.
The Attempt at a Solution
I've tried all sorts of debauchery but nothing seems to work. I have tried splitting this up and looking at it different ways, but nothing I've come up with is correct.
Homework Statement
Show that a finite commutative ring with no zero-divisors and at least two elements has identity.
Homework Equations
See above.
The Attempt at a Solution
So I need to show it is finite (easy), commutative, no zero-divisors, and and at least two elements has identity.
I define some ring R with no zero-divisors and at least two elements. Let a,b be in R. There exists a*a=1; a*b= a (or b). If a*a=a, then a*a*b=a*b...
Here I just keep running in circles.
Homework Statement
Prove that (x) in Q[x] is maximal.
Homework Equations
Q is the set of all rationals.
http://en.wikipedia.org/wiki/Maximal_element"
The Attempt at a Solution
Nothing. =[
Thank you for all the help!
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