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I was just wondering, is the equilibrium of a spring when there is no force applied or when there is a mass on it and it is in equilibrium?
Thankyou.
Thankyou.
The equilibrium position for a spring is the position at which the spring is neither stretched nor compressed. At this point, the forces acting on the spring are balanced, resulting in a state of equilibrium.
The equilibrium of a spring is affected by two main factors: the force applied to the spring and the mass attached to the spring. The force applied to the spring determines the amount that the spring is stretched or compressed, while the mass attached to the spring affects the strength of the force exerted on the spring.
The force applied to a spring determines the amount that the spring is stretched or compressed. The greater the force applied, the more the spring will stretch or compress. This will result in a new equilibrium position for the spring.
The mass attached to a spring affects the equilibrium by changing the strength of the force exerted on the spring. The greater the mass, the stronger the force exerted on the spring, resulting in a new equilibrium position for the spring.
Hooke's Law states that the force exerted by a spring is proportional to the displacement of the spring from its equilibrium position. This means that as the spring is stretched or compressed, the force exerted by the spring will increase or decrease accordingly. Therefore, Hooke's Law is directly related to the equilibrium of a spring as it explains the relationship between the applied force and the resulting displacement of the spring.