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P does equal NP? |
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| Jun8-12, 09:06 AM | #1 |
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P does equal NP?
So I really know very little about the subject but from the little I could gather online...
Consider the subset problem on wikipedia. Does a subset of {−2, −3, 15, 14, 7, −10} equal zero? It shows the work for you and then says that no algorithm to find it in polynomial time is known, only in exponential (with (2^n)-1 tries) It says that an algorithm can only exist in polynomial time if P=NP. So now, can we not set (2^n)-1=n^x so that the algorithm in polynomial time is n^((log((2^n)-1)+2i∏c)/(log(n)) where c∈Z, Z being the set of integers. Does that make any sense? |
| Jun8-12, 09:50 AM | #2 |
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Mentor
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| Jun8-12, 11:28 AM | #3 |
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| Jun8-12, 05:58 PM | #4 |
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Mentor
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P does equal NP?
Which wikipedia article were you reading? I provided a link to the one I thought you were referring to, but I don't see in that one some of what you're talking about.
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| Jun9-12, 12:42 AM | #5 |
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It was in the p versus np problem page specifically, http://en.m.wikipedia.org/wiki/P_versus_NP_problem here. It's in the third paragraph. But was the work that I did correct/incorrect? I'm sure that there's a flaw in my approach to the problem somewhere seeing as it's so simple...
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| Jun10-12, 04:13 AM | #6 |
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Never mind, I saw what my flaw was.
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| millenium problems, p versus np, p=np, polynomial, time |
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