- #1
gfd43tg
Gold Member
- 950
- 50
Hello,
I am confused about the following scenario.
Suppose I have the reaction
CO (g) + 2H2 (g) → CH3OH (g)
and I am asked to solve for the heat of reaction at 800 C. My query is the following: when finding the heat of reaction at standard state, which heat of formation I should use for the methanol? The heat of formation for gaseous or for liquid methanol?
The reason I may argue for liquid is because at standard state, methanol exists as a liquid. On the other hand, the reaction gives it as a gas. Which one do I choose and why? What's the rule about this sort of situation?
I am confused about the following scenario.
Suppose I have the reaction
CO (g) + 2H2 (g) → CH3OH (g)
and I am asked to solve for the heat of reaction at 800 C. My query is the following: when finding the heat of reaction at standard state, which heat of formation I should use for the methanol? The heat of formation for gaseous or for liquid methanol?
The reason I may argue for liquid is because at standard state, methanol exists as a liquid. On the other hand, the reaction gives it as a gas. Which one do I choose and why? What's the rule about this sort of situation?