- #1
Rahmuss
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Homework Statement
In Problem 4.3 you showed that
[tex]Y^{1}_{2}(\theta , \phi) = -\sqrt{15/8\pi} sin\theta cos\theta e^{i\phi}[/tex]
Apply the raising operator to find [tex]Y^{2}_{2}(\theta , \phi)[/tex]. Use Equation 4.121 to get the normalization.
Homework Equations
[Eq. 4.121] [tex]A^{m}_{l} = \hbar \sqrt{l(l + 1) - m(m \pm 1)} = \hbar \sqrt{(l \mp m)(l \pm m +1)}[/tex].
The Attempt at a Solution
So, I think my problem, in part, is that I don't know what they mean when they say "Use Equation 4.121 to get the normalization." So, with that in mind I did try something; but it seems too simple:
[tex]L_{+} Y^{1}_{2}(\theta , \phi) = \epsilon \sqrt{\frac{(2l + 1)(l - |(m+1)|)\fact}{4\pi(l + |(m+1)|)\fact}} e^{i(m+1)\phi} P^{(m+1)}_{l}(x)[/tex]
So, everywhere I have just [tex]m[/tex], I add one to it, which really just gives me the formula for [tex]Y^{2}_{2}[/tex]. Then solving it is simple. So I must not be understanding the question properly. And I don't see what equation 4.121 has to do with anything. I'm used to noramlization being something like:
[tex]1 = \int^{\infty}_{-\infty}|\psi|^{2} dx[/tex]
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