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luffy3san
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Homework Statement
A billiard ball of mass 0.162 kg has a speed of 1.86 m/s and collides with the side of the billiard table at an angle of 51.8°. For this collision, the coefficient of restitution is 0.841. What is the angle relative to the side (in degrees) at which the ball moves away from the collision?
m = 0.162 kg
vi = 1.86 m/s
θ = 51.8°
CR = 0.841
Homework Equations
CR = v/u
mvxi + mvyi = mv'xf + mv'yf
The Attempt at a Solution
CR = v/u
0.841 = v / 1.86 m/s
v = 1.56 m/s
mvxi = mvxf
mvcosθ = mvcosθ'
1.86 * cos 51.8° = vxf
vxf = 1.15 m/s
cosθ' = vxf/v
cosθ' = 1.15/1.56
θ' = cos-1(1.15/1.56) = 42.5°
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