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I've tried squaring both sides, then moving the RHS to the LHS, then factorizing according to a2-b2=(a+b)(a-b).
I simplified, and got
((2x+1)/(x+2))((-3/(x+2)) < 0
Then there are 2 cases:
((2x+1)/(x+2)) < 0 and ((-3/(x+2)) > 0
or
((2x+1)/(x+2)) > 0 and ((-3/(x+2)) < 0
I'm not really sure how to go from here...
Please reply ASAP!
I simplified, and got
((2x+1)/(x+2))((-3/(x+2)) < 0
Then there are 2 cases:
((2x+1)/(x+2)) < 0 and ((-3/(x+2)) > 0
or
((2x+1)/(x+2)) > 0 and ((-3/(x+2)) < 0
I'm not really sure how to go from here...
Please reply ASAP!