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Why must exponents be dimensionless? |
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| Feb8-13, 06:19 AM | #1 |
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Why must exponents be dimensionless?
suppose we have ab
why must 'b' be dimensionless? Mathematicians have defined crazy things over the centuries so why haven't they defined this one? |
| Feb8-13, 07:08 AM | #2 |
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"Dimensions", in the sense that you are using the word (meters, kilograms, degrees Celcius) are not mathematical objects, they are physical. If you are asking why no physics formula, with exponents, has no units on the exponent, you will have to ask a physicist.
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| Feb8-13, 07:45 AM | #3 |
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I see, thank you sir.
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| Feb8-13, 08:33 AM | #4 |
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Why must exponents be dimensionless?$$e^x=\sum_n \frac{x^n}{n!}=1+x+\frac{x^2}{2!}+...$$ Now does that sum make sense if x has a dimension? However the exponent can contain variables with dimensions but they must cancel to give a dimensionless number: eg. $$M(t)=M_oe^{-\lambda t}$$ |
| Feb8-13, 09:48 AM | #5 |
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Mentor
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The volume of a cube whose edge length is s is V = s3 = s * s * s. The units are tied to the variable s. All the exponent does is keep track of how many factors of s are present. |
| Feb8-13, 12:03 PM | #6 |
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\Sigma works, though \sum tends to work a little better. |
| Feb8-13, 12:10 PM | #7 |
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Fixed it now |
| Feb8-13, 01:36 PM | #8 |
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There are matrix exponentials for a given matrix X of nxn dimensions defined similarly to the ordinary exponential of a number.
eX = [itex]\sum[/itex][itex]^{∞}_{k=0}[/itex] [itex]\frac{1}{k!}[/itex] Xk |
| Feb8-13, 02:10 PM | #9 |
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Mentor
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Sigma is uppercase (##\Sigma##). |
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