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Equilibrium Constant Table Method |
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| Mar8-13, 10:19 AM | #1 |
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Equilibrium Constant Table Method
Hi, I just want someone to explain this table to me please, I am totally confused especially with the Change(mol).
Question below:
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| Mar8-13, 11:03 AM | #2 |
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If 1 Mole of NH3 is produced, how many moles of N2 and H2 were used to do that?
Hint: Use the molar ratio. If you know the initial quantity and the change, you get the quantity at equilibrium. |
| Mar8-13, 11:25 AM | #3 |
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How?, still a bit confused. Could you show me?
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| Mar8-13, 11:29 AM | #4 |
Recognitions:
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Equilibrium Constant Table Method
Is "how" related to the quantity at equilibrium?
This is a simple addition. If you start with X moles and produce Y moles, you have X+Y moles. Is "how" related to the other part? Just keep in mind that the total number of atoms (both for N and H) cannot change. |
| Mar8-13, 11:44 AM | #5 |
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I mean the Change, how do they get the change?
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| Mar8-13, 12:12 PM | #6 |
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To produce 2 molecules of NH3, you need 1 molecule of N2 (to have 2 N atoms).
To produce 1 molecule of NH3, you need 1/2 molecule of N2. To produce 1 mole of NH3 (this is given), you need 1/2 moles of N2. It is that easy. |
| Mar8-13, 12:24 PM | #7 |
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Okay I understand it now, mole ratio N2:NH3 1/2*1=0.5 and H2:NH3 3/2*1=1.5, the signs are negative because they are being used up right?
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| Mar9-13, 12:19 PM | #8 |
Recognitions:
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Correct.
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| Mar10-13, 06:01 AM | #9 |
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What would happen if the change is negative for NH3, Would it now mean that NH3 is being reversed back into its reactants and the reactants would be positive?
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| Mar10-13, 01:15 PM | #10 |
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You would need some initial NH3 for that.
In that case: Right. |
| Mar11-13, 03:19 AM | #11 |
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Okay I think thats it, Thanks for your help
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