- #1
Jacob87411
- 171
- 1
A grinding wheel is in the form of a uniform solid disk of radius 7.01 cm and mass 1.90 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.591 Nm that the motor exerts on the wheel.
(a) How long does the wheel take to reach its final rotational speed of 1190 rev/min?
Take torque = I * angular acceleration
I=. 5MR^2
.591 = (.5*1.9*.0701^2)(a)
a=126.6
So 1190/126.6 = 9.4 Seconds
Is there a problem with the logic here?
(a) How long does the wheel take to reach its final rotational speed of 1190 rev/min?
Take torque = I * angular acceleration
I=. 5MR^2
.591 = (.5*1.9*.0701^2)(a)
a=126.6
So 1190/126.6 = 9.4 Seconds
Is there a problem with the logic here?