- #1
junkie_ball
- 25
- 0
Hi newbie question,
I'm trying to work through an example of a equation where circular motion can be expressed . I'm having difficultly understanding where the next line in the equation comes from. I have shown them below. My goal is to express 'V' although currently i am a few steps away from this.
Line 1
mgr + 0.5m(2[itex]\sqrt{}rg[/itex])2 = 0.5mv2
Line 2
gr + (2[itex]\sqrt{}rg[/itex])2 / 2 = 0.5v2
I can follow the equation such that i understand both 0.5m cancels out from both sides but i get lost when i try to figure out how i lose the m from the mgr expression in line 1 from line 2?
I'm trying to work through an example of a equation where circular motion can be expressed . I'm having difficultly understanding where the next line in the equation comes from. I have shown them below. My goal is to express 'V' although currently i am a few steps away from this.
Line 1
mgr + 0.5m(2[itex]\sqrt{}rg[/itex])2 = 0.5mv2
Line 2
gr + (2[itex]\sqrt{}rg[/itex])2 / 2 = 0.5v2
I can follow the equation such that i understand both 0.5m cancels out from both sides but i get lost when i try to figure out how i lose the m from the mgr expression in line 1 from line 2?