Register to reply

Asking about matrix division

by Sledge
Tags: division, matrix
Share this thread:
Mar17-14, 08:36 AM
P: 1
Is it possible to compute matrix (A/B) without first finding the inverse of matrix B but ending with EITHER { A * (Inverse of B) } OR { (Inverse of B * A }....i think i discovered the trick
Phys.Org News Partner Mathematics news on
Heat distributions help researchers to understand curved space
Professor quantifies how 'one thing leads to another'
Team announces construction of a formal computer-verified proof of the Kepler conjecture
Mar17-14, 09:11 AM
P: 15,170
Another way to write ##X=A/B \equiv AB^{-1}## is ##XB=A##. This has a unique solution X if B is not singular. You can solve for X in XB=A using Gaussian elimination.

Another way to write ##X=B \backslash A \equiv B^{-1}A## is ##BX=A##. This, too, has a a unique solution X if B is not singular. You can solve for X in BX=A using Gaussian elimination.

What if B is singular? The standard approach is to use the pseudo-inverse, and now you have but no choice to compute that inverse, typically via singular value decomposition.

Register to reply

Related Discussions
Transition from lower division to upper division as a physics major Academic Guidance 0
Difficulty of lower division courses vs. upper division (undergraduate) Academic Guidance 10
Simple matrix division in Matlab Programming & Computer Science 2
Optimal division of a matrix for processing General Math 4
Matrix Division? General Math 5