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sara_87
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Homework Statement
A particle is projected at an angle alpha above the horizontal from a point on the edge of a table of height h standing on a horizontal floor. The particle reaches the floor at a point whose horizontal distance from the point of projection is 2h. Show that when it strikes the floor, the inclination theta below the horizontal of its direction of motion is given by
tan(theta) = tan(alpha) + 1
The Attempt at a Solution
okay i can manage to prove upto :
tan(theta) = tan(alpha) - gt/vi cos(alpha)
but i don't know what to do next... or rather what i do next doesn't make the fraction part equal 1
help would be much appreciated
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