Electrostatic field ( Gauss Law )

By ignoring the y-component, you are essentially projecting the point P onto the line of charge and finding the distance between the two. This is why your method works. In summary, to find the electric intensity at a point, we can use the formula E = (rho / (2*pi*epsilon0*r), where rho is the charge density, epsilon0 is the permittivity of free space, and r is the distance between the point and the line of charge. By projecting the point onto the line of charge, we can simplify the calculation by ignoring the y-component. This is why the answer given is -0.18(ax0.6 + az0.8)(V/m).
  • #1
Saru
4
0

Homework Statement


Assuming that an infinitely long line charge of 50(pC/m) parallel to the y-axis at x=2(m) and z=1(m), determine the electric intensity at the point (-1, 5, -3).

The answer given : -0.18(ax0.6 + az0.8)(V/m)

Homework Equations


Electric field intensity due to an infinite straight line charge of uniform density :
E= ar("rho" / (2"pi""epsolon 0"r) ( V/m)

The Attempt at a Solution



I let point P = -ax + ay5 - az3
Point on line perpendicular to point P, Q = ax2 + az

Vector Q to P = -ax3 + ay5 - az4

I found out that if i ignore or make coefficient of ay to zero and apply the above formula i'll get the answer..

but i do not understand why..please help
 
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  • #2
Hi Saru,

Draw a picture and you will see the reason immediately. You are not looking for the distance from P to Q, but from P to the line of charge.
 
  • #3
The reason why you can ignore the coefficient of ay in this problem is because the line charge is parallel to the y-axis. This means that the electric field at point P will only have a component in the x and z directions, since the line charge is not affecting the electric field in the y direction. Therefore, the coefficient of ay in the answer is zero.
 

What is an electrostatic field?

An electrostatic field is a type of force field that exists around electrically charged particles. It is created by the interaction between positive and negative charges, and it can be thought of as the space in which electrically charged objects can exert forces on each other.

What is Gauss Law?

Gauss Law is a fundamental law in electromagnetism that relates the electric field to the distribution of electric charges. It states that the electric flux through any closed surface is equal to the total charge enclosed by that surface, divided by the permittivity of free space. Mathematically, it can be expressed as ∮E⃗ · dA⃗ = Qenc/ε0.

How is Gauss Law used to calculate the electric field?

By using Gauss Law, we can calculate the electric field at a point by knowing the charge distribution around that point. This can be done by choosing a closed surface (known as a Gaussian surface) that encloses the point of interest, and then calculating the electric flux through that surface. The value of the electric field can then be determined by solving the equation ∮E⃗ · dA⃗ = Qenc/ε0 for E⃗.

What is the significance of Gauss Law?

Gauss Law is significant because it provides a simple and efficient way to calculate the electric field in many situations. It also helps us understand the relationship between electric charges and the resulting electric field. Additionally, it is a fundamental principle in the study of electromagnetism and is used in the development of many important equations and concepts in this field.

Can Gauss Law be applied to all situations?

No, Gauss Law can only be applied to situations where the electric field and charge distribution have some symmetry. This means that the electric field must have a predictable pattern and the charge distribution must have some kind of symmetry, such as spherical, cylindrical, or planar symmetry. In situations without symmetry, other methods must be used to calculate the electric field.

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