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Homework Statement
A worker drags a crate across a factoryt floor by pulling on a rope tied to the crate. The worker exerts a force of 450 N on the rope, which is inclined 38 degrees to the horizontal, and the floor exerts a horizontal frictional force on 125 N that opposes the motion. You can assume the crate doesn't leave the ground.
Calculate the acceleration of the crate (mass = 310 kg).
Homework Equations
F = ma
The Attempt at a Solution
Broke the force of the pull into x and y components:
Fx = 450 cos 38 = 354 N
Fy = 450 sin 38 = 227 N
Then the friction opposes motion, so subtract that from the x component
Fx = 354 - 125 = 229 N
so the net force is [tex]\sqrt{229^2 + 227^2}[/tex] = 322 N
then, [tex]a = \frac{F}{m} = \frac{322}{310} = 1.0 ms^{-2}[/tex] to 2 s.f.
However the answer given is 0.74 ms