Complicated path question - 2D vectors

In summary, the conversation discusses a model car moving on a horizontal track and its displacement from a fixed origin at different times. The car's displacement is given by r(t)=2cos(t)i + sin(2t)/sqrt2j, where 0<t<2pi. The conversation covers the physical significance of r . r and how d(r.r)/dt can be used to determine the maximum distance of the car from the origin. It also addresses the number of times the car passes through the origin in the given time interval, as well as determining the velocity and acceleration of the car at a given time and the times at which the velocity is perpendicular to the displacement. The conversation ends with a request for help and clarification on part (
  • #1
Kawakaze
144
0

Homework Statement



A model car of mass m moves on a horizontal track so that its
displacement r from a fixed origin at time t is given by

r(t)=2cos(t)i + sin(2t)/sqrt2j where 0<t<2pi

(a) If r is the position vector of a particle, explain the physical
significance of r . r and show how d(r.r)/dt can be used to determine
the maximum distance of the car from the origin.

(b) Show that the car passes through the origin exactly twice in the time interval and determine the two times.

(c) Determine the velocity and acceleration of the car at time t.

(d) Determine the times at which the velocity of the car is perpendicular
to its displacement and the position vector of the car at these times.

The Attempt at a Solution



(a) Unsure of significance, but its pretty clear that when d(r.r)/dt = 0 you have your maximum and minimum distances from the origin.

(b) No idea how to prove this but I guess its obvious that you would have two solutions in the interval 0<t<2pi.

(c) No problem, differentiate once for velocity and twice for acceleration.

(d) This looks like a fun part, but no idea how to calculate this. You want the vectors to be at 90 degrees to each other.

Help please! :)
 
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  • #2
Remember that two vectors are perpendicular when their dot product is zero.
 
  • #3
I know this is what i need to do, is there any worked examples online you know of?

Also still no idea about part (a)
 

1. What is a 2D vector?

A 2D vector is a mathematical concept that represents a quantity with both magnitude and direction in a two-dimensional space. It is typically represented by an arrow pointing from the origin to the desired point, with the length of the arrow corresponding to the magnitude and the direction of the arrow indicating the direction.

2. What makes a path complicated in terms of 2D vectors?

A path is considered complicated in terms of 2D vectors when it is not a straight line and requires multiple vector calculations to determine its direction and magnitude. This can occur when the path has several turns or changes in direction, making it difficult to determine the overall direction and magnitude of the path.

3. How do you calculate the direction of a complicated 2D vector path?

The direction of a complicated 2D vector path can be calculated by breaking the path into smaller, simpler segments and determining the direction of each segment. Then, using vector addition, the individual segment directions can be combined to determine the overall direction of the path.

4. Can a 2D vector path have a negative magnitude?

Yes, a 2D vector path can have a negative magnitude. This occurs when the path is moving in the opposite direction of the reference point. For example, if the reference point is at the origin and the path is moving towards the negative x-axis, the magnitude of the path will be negative.

5. How are 2D vector paths used in real-life applications?

2D vector paths are used in various real-life applications, such as navigation systems, video game development, and physics calculations. They are particularly useful in situations where there is movement or displacement in two dimensions, and the direction and magnitude of the movement need to be determined.

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