- #1
Reshma
- 749
- 6
This one is again from Griffiths.
a) Find the force on a square loop of side 'a' placed at a distance 's' from an infinite wire. Both the loop and the wire carry a current 'I'.
I found the magnitude of the magentic field using Biot-Savart's law:
[tex]B = \frac{\mu_0 I}{2\pi s}[/tex]
The force is given by:
[tex]\vec F_{mag} = I\int\left(d\vec l \times \vec B\right)[/tex]
"dl" is a wire element.
So, when I consider only the magnitude:
[tex]F = \frac{\mu_0 I^2}{2\pi s}\int dl[/tex]
Here the wire is infinite, so how is it possible to integrate over the length of the wire?
a) Find the force on a square loop of side 'a' placed at a distance 's' from an infinite wire. Both the loop and the wire carry a current 'I'.
I found the magnitude of the magentic field using Biot-Savart's law:
[tex]B = \frac{\mu_0 I}{2\pi s}[/tex]
The force is given by:
[tex]\vec F_{mag} = I\int\left(d\vec l \times \vec B\right)[/tex]
"dl" is a wire element.
So, when I consider only the magnitude:
[tex]F = \frac{\mu_0 I^2}{2\pi s}\int dl[/tex]
Here the wire is infinite, so how is it possible to integrate over the length of the wire?